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IshaSQL

Foundations Track · Easy · 15 min

Customer Placing the Largest Number of Orders

Table: Orders +-----------------+----------+ | Column Name | Type | +-----------------+----------+ | order_number | int | | customer_number | int | +--------...

Foundations Track
Easy
15 min
aggregation

Company labels are directional practice context, not official interview guidance.

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Objective

Practice aggregation through a IshaSQL-tagged business scenario.

Approach

Use this track to lock in clean query structure, basic filtering logic, and confidence with grouped output.

Company context

Company labels are directional practice context, not official interview guidance.

Prereq: query basics
Prereq: filtering

Table: Orders +-----------------+----------+ | Column Name | Type | +-----------------+----------+ | order_number | int | | customer_number | int | +-----------------+----------+ order_number is the primary key (column with unique values) for this table. This table contains information about the order ID and the customer ID. Write a solution to find the customer_number for the customer who has placed the largest number of orders . The test cases are generated so that exactly one customer will have placed more orders than any other customer. The result format is in the following example. Example 1: Input: Orders table: +--------------+-----------------+ | order_number | customer_number | +--------------+-----------------+ | 1 | 1 | | 2 | 2 | | 3 | 3 | | 4 | 3 | +--------------+-----------------+ Output: +-----------------+ | customer_number | +-----------------+ | 3 | +-----------------+ Explanation: The customer with number 3 has two orders, which is greater than either customer 1 or 2 because each of them only has one order. So the result is customer_number 3. Follow up: What if more than one customer has the largest number of orders, can you find all the customer_number in this case?

Orders
order_number INT PRIMARY KEY
customer_number INT
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